Khan will destroy McClosky in Salita fashion

[Chip2006uk]

I have £14 spread on Khan by TKO/KO in rounds 1-7

[BoxerDood]

Exactly. McCloskey is no pushover. If he can survive the first 4 rounds, Amir may be in for a long night.

That's a HUGE if though. I mean what does he bring to the table that allows him to survive those rounds? He keeps his hands low a lot and is easy to hit, he's smaller and doesn't bring anything dangerous to the table that will keep Khan off of him. He can shoulder roll all he wants but it won't get him anywhere against the second fastest boxer in the world.

[z0jo]

has mccloskey ever been hurt before? if so I got khan winning by early stoppage.

[BoxerDood]

has mccloskey ever been hurt before? if so I got khan winning by early stoppage.

He's been on the canvas before. And he's also a slow starter.

[PrinceNaz88]

I can't see it going any other way. It's one of those "anything you can do, I can do better" type fights, just like the Malignaggi fight, only he won't be fighting an experienced, iron chinned, battle tested boxer. McCloskey has never been down this type of road, and he won't know what to do against Khan's lightning fast hands. If he makes it to the second round, it'll be because he survived after getting put down a few times, or Khan started off slow.

If Paul gives him a good fight, then props to him. I'll be happy to eat my words. But my prediction is a TKO within 3 rounds for Amir. First round is likely.

Completely agree.

It will be a quick fight in my opinion leaving those attending M.E.N and watching on Primetime feeling ripped off with the poor undercard thrown in...

[Uturn]

If your short of cash then I suggest you get on at 14/1 for khan in round 1, easy money here lads...

[PrinceNaz88]

If your short of cash then I suggest you get on at 14/1 for khan in round 1, easy money here lads...

I've done 9/4 Khan inside 4 rounds..

Playing it safe

[fight_professor]

Someone hook me with a means to view this. Mucho props to anyone who does that. Oh and 5k points too. Plus +K.