Miguel Cotto: "Me and Pacquiao Will Be a War"

[Stoppage]

Cotto is getting in the war mindframe.

I don't know if Pacquiao is doing the same thing. IMO, he's starting training a bit too late.

[Haglerwins]

Cotto is classes above Hatton.

You think Hatton could go those rounds with Margarito, outbox Mosely or go to war with Clottey? No to mention the brutalisation of guys like Quintana.

^ Yep. Hatton barely got by a 147 gatekeeper. He loses to just about all of those you mentioned in the early rounds.

[JM1]

Cotto is getting in the war mindframe.

I don't know if Pacquiao is doing the same thing. IMO, he's starting training a bit too late.

the fight is on nov 14 and pac will start his camp come first week of september. he normally train for 8weeks

[Irish_Frank]

Can see this fight going the distance with Pac working the angles and moving away. Cotto has to pull away early and keep with Pac in the later rounds to have a chance. I see Pac winning by 2/3 rounds. I think Cotto will hurt Pac its just how Cotto's face holds up coming in and out.

[JM1]

Cotto is classes above Hatton.

You think Hatton could go those rounds with Margarito, outbox Mosely or go to war with Clottey? No to mention the brutalisation of guys like Quintana.

nobody said that hatton is better than cotto

[Matt Marvelous]

I can't believe people think Cotto is tough enough to take Pacquiao's shots for 12 rounds. It baffles me.

[Haglerwins]

I can't believe people think Cotto is tough enough to take Pacquiao's shots for 12 rounds. It baffles me.

The man got hit with rocks for 11 rounds.

[DiLLiNGER]

if pacquiao loses this one no one will give him credit for his last 3 or 4 wins.

[Matt Marvelous]

The man got hit with rocks for 11 rounds.

Pac is going to land a lot more than Margarito did.

[Haglerwins]

nobody said that hatton is better than cotto

No, but he has been labeled "overrated" by Cotto. It's easy to back that up when you size Ricky up to Cotto's level of opposition. He wouldn't make it out of the early rounds with the majority of them.