Former WBO heavyweight champion Joseph Parker (24-1, 18 KOs) could be looking for a touch of domestic revenge in his next fight.

According to a report by Stuff, giant-sized contender Alexander Ustinov (34-2, 25 KOs) of Russia is being mentioned as a potential opponent for the New Zealand star.

Ustinov fought in New Zealand in 2013, when he dominated another local star, David Tua, and retired the veteran with the loss.

The 6'7 boxer was riding a seven fight win streak - until he was dropped and outboxed by Manuel Charr last November in Germany.

His other defeat came in 2012, when he was knocked out by top rated contender Kubrat Pulev.

Parker would also be coming off a loss, after losing a twelve round unanimous decision to Anthony Joshua in March - when they fought in an IBF, IBO, WBO, WBA heavyweight unification clash.

As previously reported, Parker's promoter David Higgins is looking to stage his next fight in New Zealand.

Ustinov is ranked at 10 with the WBA, and because of the win over Tua he would be a very marketable opponent to sell tickets for the event.

"The absence of a good opportunity in the UK would necessitate looking at New Zealand and whether we can mount a credible promotion here with a big name opponent," Higgins told New Zealand Radio.

"[Joseph's next opponent] is someone that's big and tall, because a lot of the top guys are big and tall and he can learn from his mistakes [against Joshua]. It's ideally someone in the top 15 or top 10 of the sanctioning bodies and someone with a name that's promotable."

Higgins would like to match Parker against Tony Bellew, who last weekend stopped David Haye, but he doubts the Liverpool boxer would take the fight.

Bellew was calling for a fight when Parker was the WBO world champion, but lately he's been calling for Andre Ward and Tyson Fury.