Comments Thread For: Caleb Plant: I'm The Big Dog at 168 - I'm Not Chasing Nobody!

[Ray*]

Stop crying like a little *****. It’s obvious boxing isn’t the sport for you.

Awww..You seem to be caught up in emotions here

[JonDP]

Will this fight show anything that Canelo is not going to DEMOLISH in a few month’s time?

[Bandman]

boxing sucks ass.

this unproven bum is a top dog?

Imagine an unproven bum in UFC calling himself top dog. Never happens

[patron]

Nor is mr plant unifying any titles, you know big dog shyt.

[Fighter78]

I'm gonna go out on a very short and strong limb and say that I don't believe Caleb Plant even stops Caleb Truax. UD in 12

[jonnyc420]

boxing sucks ass.

this unproven bum is a top dog?

Imagine an unproven bum in UFC calling himself top dog. Never happens

You mean like Nate Diaz does? Never won a championship and loses half his fights. It's obvious you do not like boxing so why are you here? To troll, but dude you suck at that. I suggest you give it up.

[KING5TWENTY]

Actually happens likes every other weekend in the ufc

[Verus]

Hopefully Plant's plan is not to hide behind his title indefinitely

Caleb Plant seems to be following the Billy Joe Saunders playbook.

[hitmanjosh]

Caleb is good and smooth but,

Canelo is the big dog and then you have David Benavidez followed by you. Although I believe David is the real deal and best fighter in the division, it’s Canelo that brings the bacon with the biggest following and most accomplished. Caleb can fight but still a bit unproven on a championship level.

[Fire4231]

Really like this kid. Willing to fight anyone. The opposite of Canelo who avoids the two hardest styles in boxing. He won’t fight Slick Boxer Punchers and he won’t fight other Mexican fighters.

Btw- He also won’t fight Mandatories unless he chooses them and he had decided not to fight GGG.

In addition...He never fights the top guys in the division. Canelo is showing up like smoke and mirrors earning belts against mediocre fighters in the division and moving on the duck path.