Oscar De La Hoya "negotiations are complicated because gg thinks hes a superstar"

[RED REP]

LOOK phagget, not even an D level fighter takes 90-10 you son of a whore drag. COWARD, you and Canelo both. Scared cowards. GENNADY is the MANDATORY for Canelos 160 title you ******* addict low life.

Give over, you Pacquiao fanboy.

[aldo5408]

Far as I'm concerned, the superstars of boxing are Canelo, Chocolatito, GGG, Crawford, and Wilder.

You're dead wrong. Roman, gg, Crawford and wilder are not stars at All not even a little bit

[anonymous2.0]

You're dead wrong. Roman, gg, Crawford and wilder are not stars at All not even a little bit

boxingscene wouldnt lie to me

[Kenchiro]

Canelo will fight ggg on a weight both fighters will agree on...canelo refuses to fight ggg the he gets strip...if wbc don't strip canelo n make ggg champ then there's always the court....team ggg will take the wbc to court n win there....damn never seen such legendary ducking....

[Nay_Sayer]

From 2 years ago.
@1:22

He was only kidding.

Lol..

[Nay_Sayer]

^ Did you all ever notice that people who hate Golovkin (and call him "Mr. 97K") are always the ones who can't spell, use proper grammar, or capitalize?

Just a random musing ...

Also did anyone know that the source of that 97K rumor also claimed Canelo-Cotto didn't break 600K? Funny how haters run with one rumor and run away from the other--even though the rumors stem from the same source!!!

Watch them all ignore this post.

Do you have the official PPV numbers for the Bumlovkin Lemieux fight? If so, please post them here...

[aldo5408]

Hopefully team gg stops being so difficult to negotiate with and accept Oscars terms if they are reasonable
80-20 split etc

[aldo5408]

HeroBando
here Oscar is explaining the situation more clearly

[Chuckguy]

Hopefully team gg stops being so difficult to negotiate with and accept Oscars terms if they are reasonable
80-20 split etc

60-40 split sounds fair.

[respectthebrush]

70-30 make the fight at 158. Hehe...GGG was 159 for this last weigh in.