Comments Thread For: Kell Brook Vows To Break Mayweather's 49-0 Record

[Pac=Duran]

It doesn't mean anything if you're just fighting bums.

Kell Brook notable wins by 35-0:

Shawn Porter

Mayweather notable wins by 35-0:

Corrales
Castillo I & II
Gatti
Judah
Corley

Kell Brook might get to 70-0+ if he keeps raiding homeless shelters and lap-top repair men conferences for his opponents.

[Box-Office]

You're very confused.
Anyway, Brook should write Khan a letter for being recognized as the 10th best fighter in the world and being world champion.

After all, if Amir Khan wasn't around, nobody would have ever known Kell's name.

Bradley's only loss was to arguably the 2nd best guy of this generation, Pacquiao. Brook's only relevant win was Porter. Kell is top 10 P4P and rated above Bradley at WW. Stop embarrassing yourself with "this opponent was ranked at this" or "that guy was ranked at that" talk.

[lfc19titles]

as if this knob could not get more insufferable

he will fight bus drivers till he is 100-0 as brook diggler will be with him all the way sucking him dry

[Dirk Diggler UK]

as if this knob could not get more insufferable

he will fight bus drivers till he is 100-0 as brook diggler will be with him all the way sucking him dry

Khantards mention me in all their posts

I've left an entire fanbase in ruins

[IMDAZED]

Possible if he continues this quality of opposition.

[wlliam]

Khantards mention me in all their posts

I've left an entire fanbase in ruins

Its not their fault theyve been Khan'd

[bigjavi973]

[MrRolltide91]

Possible if he continues this quality of opposition.

yep........

[Brickyardigan]

I don't understand this whole 49-0 thing.

If brook keeps fighting the level of comp he is facing he will be 120-0.

Wasn't Chavez sr 90-0 when he first lost?

If brook steps it up and beats the big names in the welterweight division then it would be something.

Floyd has an good resume to make it look like an good accomplishment.

Chavez Sr. record is padded with scrubs about time he got to that record.