Comments Thread For: HBO Pledged To Put on Better PPV Undercards

[George Orwell]

no reason why they couldnt add a Mikey Garcia or something, would be a great boost to the card.

[ShoulderRoll]

How many times could Nonito Donaire have been featured on a Pac ppv? And that's just one example, Arum missed the boat on a lot of potentially good cards.

[DoktorSleepless]

How many times could Nonito Donaire have been featured on a Pac ppv? And that's just one example, Arum missed the boat on a lot of potentially good cards.

Michael Konz cock blocked Donaire from being on Pac undercards.

[SaldanaCC]

Finally this is being adressed!!!!!!!!!
Showtime is killing hbo with there undercards in my opinion every co main event should be for a title of some sort or 2 highley ranked fighters seems to me only floyd undercards know how to give the fans there moneys worth in the co featured bouts.
****ty undercards made the ufc loose a ton of fans and money hbo better learn from dana!!!!!!!

[LouIE G]

It's with out a shadow of a doubt that showtime and gbp have the better product.., but i can say about this card tonite is ,t that it is better then garbage top rank is used to giving us..so i cant really complain, they already got my buy!!

[ailicec]

Arum said he DIDN'T CARE about the undercards.

He said people paid to only see the main event.

[Pigeons]

This undercard ain't bad. Beltran-Usmanee is an all-action fight. Khabib-Vargas is interesting to me. Vasquez-Felix Jr. is a throw away fight for me.

[-PBP-]

That's interesting. Didn't think of that. The fights aren't particularly meaningful, but they they do have world title/HBO implications.

Still, I'm willing to bet this will be one of the most fun PPV undercards this year.

Oh yeah. I think this is pretty decent especially based on what Top Rank usually gives us.

They aren't big names but they are all top 10-15 contenders in meaningful, competitive fights. What more can you ask for?

May 3rd gives us big names in meaningless fights. I'd take this card any day of the week.