Carl Froch beats Chad Dawson at 168

[Kagami Taiga]

a bunch of you guys are saying that its a bad style match for froch but I disagree. i think you guys are saying that and assuming that all boxers will be a bad match for froch because of the ward fight. chad fights nothing like ward, he is a rangy fighter that doesn't like being pressured much and prefers not to fight on the inside.

froch would be too much pressure for dawson at 168, he would walk through him and destroy him because dawson won't have power or enough physical strength at that weight. dawson is mentally weak and the cobra is a warrior, his will is too much for a drained dawson end of story

i suggest u watch dawson/ademek

[SCtrojansbaby]

Anybody can beat Dawson at 168.

[techliam]

Id pick Froch to KO Dawson at both 168/175 if he had the determination he had in his last fight

[Mr. Philadel]

Id pick Froch to KO Dawson at both 168/175 if he had the determination he had in his last fight

his opponent was a walking KO victim....a KO waiting to happen....some dudes allowed his nuts to cover their eyes and they THOUGHT he was something special...Froch EXPOSED him....but those of us who didn't rock those nut shades saw this coming

Froch can fight with the same fire and energy against Dawson and STILL get boxed outta his misery....Dawson is NOT Bute....maybe in his teens lol but now Chad is a man...Bute is a boy who needs to be well taken care of imo....so that SAME fire won't get the SAME result when Chad Dawson is his opponent.....at '68 we don't know yet...but we do know styles make fights and Chad's style gives Froch trouble

[BoxingGenius27]

I actually voted Maybe.

It all depends on how Dawson responds to Froch's pressure and if Froch can take Dawson's punch at that weight. For all we know, Dawson might hit pretty damn hard.

I remember Dawson dropped Adamek and had him in trouble. I also remember Taylor, Kessler and Dirrel hitting Froch with some pretty good shots and arguably having him in trouble.

It would be interesting to see who succumbs.