Mayweather's Defining Moment - Which Fight?

[bojangles1987]

If we are saying defining moment, and not defining fight, I would say taking the two right hands by Mosley and dominating every second afterwards. So many though Floyd would crumple after taking shots like those, and he didn't.

[ThunderWolf]

Which of Floyd's fight against a certified all-time great - who was still in his prime and fighting without a weight and/or age handicap - made him the legendary all-time great fighter that he is?

Is this a joke?

Or do you have a mental disability?

[sweetpea87]

Definitely Calos Baldomir, if you wanna talk about some of the greatest performances of all time.

[Flomo Tard]

Is this a joke?

Or do you have a mental disability?

Are you claiming that Floyd is not an all time great because his toughest opponent was only Corales who wasn't even in the top 150 p4p of all time?

You're the one with the mental disability. Floyd is 41-0 and that's what makes him top 3 p4p in history.

[Daddy T]

i'll have to go with the majority here, the obvious answer is corrales. It was alsoprobably his best performance - would I be right in saying he was the underdog going into that one I can't remember? Either way after that fight he was never again the underdog

[jaskieee]

Diego Corales.

Yep everyone knew he was the real deal once he put the beatdown on Corales.

However the Gatti and De La Hoya fights were the ones that made him a superstar.

[ronniejunior]

it was the diego corrales fight, critics swore up and down that he was
too big for floyd and had too much power...we all know what happened

in that fight...

1st runner up would be the gatti fight...floyd showed the world
why gatti wasn't even on his level and why he was a c class club fighter


r.i.p. to diego and gatti though...

[Syf]

gatti, corrales, prime hatton, mosley

[Pin Galarga]

He had defining moments as a lightweight against Corrales, but as a welterweight his win over Mosley defined him as the #1 again.

[TRAV1$]

Retiring when 147 was competitive
No flames.