Amir Khan can beat Bradley, no problems.
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Your outta of ya mind if you think he could beat Bradley easy. I don't think he can beat him let alone easyComment
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IMO, no one at 140 beats Bradley without problems.
You point out that Khan is getting better with every fight, well Bradley is too; he's been refining his technique and skills, as well as adding and showing more dimensions to his game.Comment
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For some reason, I can just see Khan being able to box Bradley. Bradley's good, but he becomes predictable, and Khan has a lot of tools at his disposal now. I give Khan a year or two to see a dominant performance. Right now, it's Bradley's fight.Comment
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It's funny, Bradley is being hyped up to high heaven, and Khan gets shat on, i wonder why that is?Comment
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It was a good try TS, LOL. I know you would love to see Khan become this great fighter but no way against BRADLEY...All my points on Bradley if this ever happens..I can't see Warren giving up Khan to Bradley like that..LOL.Last edited by chillin8; 12-15-2009, 11:20 PM.Comment
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bradley can crack dont be fooled by the lack of kos he just sucks at finishing....khan has beat two slow bums all of a sudden hes the man at 140?Comment
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The way I see it is Bradley is not going to KO Khan for sure. The only way Bradley gets a KO is when someone walks into his punch. Khan is much to much of a technical boxer to be making amateurish mistakes as to walking into punches. Bradley always looks good, and why's that? Most of his opponents stand in front of him and allow him to rip off 5-6 punch combination's, whether or not they land, they look flashy, which will catch the casual eye. Khan will not be standing in front of Tim to allow him to unleash something like so. Bradley will have a much harder time trying to adjust to Khans speed and boxing skill. Bradley will also have a hard time dealing with Khans precision along with power. Bradleys key to victory in his entire career was for quick combinations followed by high work rate, but I believe most of Khan's attributes negate most of them.Comment
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