Who would you like to see Spadafora fight?

[Spray_resistant]

Yeah, Spady is back and I just read that he won his fight last night. I also am aware that he is 42-0-1 and has not fought very tough competition to date. So who would some of you like to see him fight, that would make for an entertaining competitive match up?

[Clegg]

Amir Khan.

It'd be nice for Spaddy to finally get a KO win.

Seriously...I dunno. Maybe someone like Kendall Holt, that's a fight that I'd watch.

[KittenFlaps]

The Burghs own Spadafora. Our native son. I'd be happy to see him fight anyone other than his girlfriend.

On a side note I got to hold his IBF belt in the deli downstairs from my ex-girlfriends apartment. It was at the deli for safe keeping while he was in jail. The deli owner is one of his promoters.

True story.

[lettdragon]

hes a thug outside the ring,but hes a dam good fighter id throw him in with floyd or manny after another warm up fight.hed have a chance.

[KittenFlaps]

I dunno about that. Maybe use Spadafora as a warm up fight for Hatton. Give him a chance to make some money, and possibly (very small chance) beat Hatton and make a name for himself.

[THE REED]

ive seen him fight twice right here in erie

[lettdragon]

I dunno about that. Maybe use Spadafora as a warm up fight for Hatton. Give him a chance to make some money, and possibly (very small chance) beat Hatton and make a name for himself.

your right that would be a great fight. for them both if hatton wins hes beat a undeafeted x champ and back in the mix at 140 .and if spadafora wins hes in the mix at the top at 140 love 2 se it.

[Teddy Brenner]

I'd like to see Spaddy fight Bobby Pacquiao.

It would be competitive and an interesting name on his record.

And if he wins....

[Puntoyhauf]

I'd like to see Spaddy fight Bobby Pacquiao.

It would be competitive and an interesting name on his record.

And if he wins....

That's an OK fight.

*your sig...MoCap? are you in the gaming industry or you just got that gif on internet?

[Dubious-Dutch]

Is he Mexican?