Kell brook: will he man up and fight Errol spence?

Brook is trying to get good fights, one being mandated would take care of those problems. Brook beats every guy at 147.

No way Brook wants this fight. Too much risk, not enough financial reward. It'd be competitive, but Brook thinks he's getting mayweather to come out of retirement or something. He's a bit delusional as to his importance on the boxingscene, he can't even get Khan to fight him who is a natural already hyped rivalry he may need a fight like this soon.

Haymon will likely line up Thurman/Porter winner for Spence, which will probably take another year. That's a problem, because Spence needs to step up into the world title pool right now. Maybe a Garcia fight? Or do we just get a bunch of bums till thurman/porter is sorted?

btw is spence the mandatory that would be funny If they vacate it. I think he is. Or #1 at least. Not sure if the last fight was a final eliminator. But Brook just fought his mandatory, so he won't have to fight Spence for another year. That means Spence has to fight in the IBF rankings to keep his position, similarly to what Brook did before the Porter fight.

btw is spence the mandatory that would be funny If they vacate it.

I think Brook is too much for Spence right now. Too big, too fast, too strong..

I think Brook would wreck Spence and then everyone will say that Spence beat nobody but Algieri and Algieri was never that good etc. etc.

We'll see. I'm pretty sure Brook would want to fight Spence in the U.K. I hope Spence makes the trip and knockout Brook in his backyard.

Obviously it's not his #1 priority. And let's wait and see how keen Haymon/Mayweather is to let him go to the UK for peanuts. My guess is they'll try and feed Broner to Spence.

Nah, he'll definitely be scouring the back alleys of Walmart for his next fight though. lmaooooo! I think they have tesco instead of walmart but I wouldnt be surprised with their next opponent.

Nah, he'll definitely be scouring the back alleys of Walmart for his next fight though.