Fight of The Year! Prediction

[magicjordan]

Pacquiao Vs Morales 2

[Da Iceman]

castillo vs. corrales 3.

[Mech.]

Cotto-Castillo I

[Easy-E]

Right Now its Mac vs Bell.

I bet Miranda v Abraham will be intense.

[Kball15]

I think Carrales Castillo 3 will win FIGHT OF THE YEAR without a doubt if the fight lasts past round 8. Im almost sure of it.

Also, De La Hoya has another fight comin up later in the year, possibly against PBF. that could be fight of the year also.

And since Hopkins is fighting to make BIG history, he might fight like he did in his prime and attack tarver non-stop. If hopkins is determined enough, we might see fight of they year on june 10th.

[Da Iceman]

I think Carrales Castillo 3 will win FIGHT OF THE YEAR without a doubt if the fight lasts past round 8. Im almost sure of it.

Also, De La Hoya has another fight comin up later in the year, possibly against PBF. that could be fight of the year also.

And since Hopkins is fighting to make BIG history, he might fight like he did in his prime and attack tarver non-stop. If hopkins is determined enough, we might see fight of they year on june 10th.

your wrong. tarver has boring style, so does hopkins. together they make the most boring sleepiest fight of the year.

[cobracore]

Hopkins lost both his last fights because he didn't do enough. Hopfully (pun intended, as bad as it was) he will learn from the mistake, come out with guns blazing and head high on June 10th, throw a picture perfect counter right, and knock Tarver the **** OUT. Because everybody hates Tarver.

[Da Iceman]

Hopkins lost both his last fights because he didn't do enough. Hopfully (pun intended, as bad as it was) he will learn from the mistake, come out with guns blazing and head high on June 10th, throw a picture perfect counter right, and knock Tarver the **** OUT. Because everybody hates Tarver.

even his mama.

[BrooklynBomber]

Fight of the year prediction:
Rockin1 vs Asian Sensation.

[Da Iceman]

Fight of the year prediction:
Rockin1 vs Asian Sensation.

it wont happen.