Comments Thread For: Roach: Canelo-Smith is More Competitive Than Golovkin-Brook!

[Boxing Logic]

Lmao I agree Freddie! And Brook is also better than Liam Smith!

So...

Brook = A
Smith = B
GGG = C
Canelo = D

If B is closer to D than A is closer to C, and A is greater than B, then it follows that C is much greater than D!

Yes, Canelo-Smith is more competitive, even though Brook is better than Smith. Which means, the reason is because GGG is way better than Canelo. Which is why marinating it as some super fight is so dumb. But I guess they will marinate long enough for GGG to decline, and then it will be competitive enough for a superfight, even though it will be meaningless because everyone will know it's only because GGG is old, and no one wants to go through with that crap again like Mayweather-Pacquiao. So really it's all bullisht.

[bigdunny1]

Lmao I agree Freddie! And Brook is also better than Liam Smith!

So...

Brook = A
Smith = B
GGG = C
Canelo = D

If B is closer to D than A is closer to C, and A is greater than B, then it follows that C is much greater than D!

Yes, Canelo-Smith is more competitive, even though Brook is better than Smith. Which means, the reason is because GGG is way better than Canelo. Which is why marinating it as some super fight is so dumb. But I guess they will marinate long enough for GGG to decline, and then it will be competitive enough for a superfight, even though it will be meaningless because everyone will know it's only because GGG is old, and no one wants to go through with that crap again like Mayweather-Pacquiao. So really it's all bullisht.

No it's because both Canelo and Smith have fought and won world titles in the SAME division. While Brook hasn't even separated himself from the pack at WW and is TWO WHOLE division smaller then GGG. The size difference is why this fight is a mismatch. And why GGG is a clown and hypocrite for criticizing Canelo for basically grabbing a WW and dragging him up 1 weight class and he turns around does worse dragging Brook up 2 full weight classes.

[aboutfkntime]

Lmao I agree Freddie! And Brook is also better than Liam Smith!

So...

Brook = A
Smith = B
GGG = C
Canelo = D

If B is closer to D than A is closer to C, and A is greater than B, then it follows that C is much greater than D!

Fk me, go change your name to ' Maths Professor ' LMAO

Canelo/Smith are both Junior Middleweights..... lil'G/Brook are TWO divisions apart.

Also, triangle theories do not work in boxing.

Yes, Canelo-Smith is more competitive, even though Brook is better than Smith. Which means, the reason is because GGG is way better than Canelo. Which is why marinating it as some super fight is so dumb. But I guess they will marinate long enough for GGG to decline, and then it will be competitive enough for a superfight, even though it will be meaningless because everyone will know it's only because GGG is old, and no one wants to go through with that crap again like Mayweather-Pacquiao. So really it's all bullisht.

OBVIOUSLY !

You should have just said that, and left it there..... without all the bs.

[Cinci Champ]

its true though mate, look at the head to head pictures

i have even tho one has a t shirt and another a big suit its still pretty dam clear to me that ggg is much larger just look at the shoulders