Before Ortiz bout FMJ knockout percentage at 147 was 17%. Is Pacquiao higher?

[texasboi15]

Who has the higher KO percentage at welterweight?

Pacquiao or Mayweather?

[gauze]

mayweather: 37.5%
pacquiao: 25%

[dc3383]

Floyds KO% at 147 wasn't 17% genius; He KO'd Sharmba Mitchell and Ricky Hatton; decisioned Mosley,Zab and Baldomir and even if you want to include a ctachweight with marquez thats still not 17% its close to 40% learn how to do some math.

[texasboi15]

Floyds KO% at 147 wasn't 17% genius; He KO'd Sharmba Mitchell and Ricky Hatton; decisioned Mosley,Zab and Baldomir and even if you want to include a ctachweight with marquez thats still not 17% its close to 40% learn how to do some math.

Floyd's KO ratio is stated at 7:18 of video:

[Hougigo]

Anything between 141-147 is WW

Floyd at WW-
Victor Ortiz- KO
Shane Mosley - UD
JMM - UD
Ricky Hatton - TKO
Baldomir - UD
Zab - UD
Sharmba Mitchell - TKO

3/7 = 43 percent

Manny Pacquiao at WW-
Shane Mosley - UD
Joshua Clottey - UD
Miguel Cotto - TKO
ODH - RTD (basically counted as a TKO)

2/4 = 50%

Huzzah for math

When they said 17 percent, they didn't count one of his victories as a KO and basically had it 1 KO in 6 fights (because they said it while he was fighting Ortiz)

[figzuki]

Anything between 141-147 is WW

Floyd at WW-
Victor Ortiz- KO
Shane Mosley - UD
JMM - UD
Ricky Hatton - TKO
Baldomir - UD
Zab - UD
Sharmba Mitchell - TKO

3/7 = 43 percent

Manny Pacquiao at WW-
Shane Mosley - UD
Joshua Clottey - UD
Miguel Cotto - TKO
ODH - RTD (basically counted as a TKO)

2/4 = 50%

Huzzah for math

When they said 17 percent, they didn't count one of his victories as a KO and basically had it 1 KO in 6 fights (because they said it while he was fighting Ortiz)

couldn't have been said better....

/ thread.....

[jayblack]

Floyds KO% at 147 wasn't 17% genius; He KO'd Sharmba Mitchell and Ricky Hatton; decisioned Mosley,Zab and Baldomir and even if you want to include a ctachweight with marquez thats still not 17% its close to 40% learn how to do some math.

Pac only had 3 fights at 147. DLH, Clottey and Mosley. So prior to the Mayweather Ortiz fight Pac had the higher percentage at 33%.

[Johnwoo8686]

Floyd's KO ratio is stated at 7:18 of video:

So just because Larry Merchant says it, that automatically makes it a fact? Come on man, actually do your own research before stating bull**** statistics. Floyd KO'd 3 guys at welterweight out of 7. Which is 43%. I guess if you exclude the Ortiz KO and count in the Oscar fight that brings his KO ratio at welterweight to 25%.

Manny knocked out 2 out of 6 guys at welter and above. Which is 33%

[jayblack]

Anything between 141-147 is WW

Floyd at WW-
Victor Ortiz- KO
Shane Mosley - UD
JMM - UD
Ricky Hatton - TKO
Baldomir - UD
Zab - UD
Sharmba Mitchell - TKO

3/7 = 43 percent

Manny Pacquiao at WW-
Shane Mosley - UD
Joshua Clottey - UD
Miguel Cotto - TKO
ODH - RTD (basically counted as a TKO)

2/4 = 50%

Huzzah for math

When they said 17 percent, they didn't count one of his victories as a KO and basically had it 1 KO in 6 fights (because they said it while he was fighting Ortiz)

The question was who has a higher percentage at 147

[Pretty Boy1]

Anything between 141-147 is WW

Floyd at WW-
Victor Ortiz- KO
Shane Mosley - UD
JMM - UD
Ricky Hatton - TKO
Baldomir - UD
Zab - UD
Sharmba Mitchell - TKO

3/7 = 43 percent

Manny Pacquiao at WW-
Shane Mosley - UD
Joshua Clottey - UD
Miguel Cotto - TKO
ODH - RTD (basically counted as a TKO)

2/4 = 50%

Huzzah for math

When they said 17 percent, they didn't count one of his victories as a KO and basically had it 1 KO in 6 fights (because they said it while he was fighting Ortiz)

What about the Margarito fight? That would make it 2/5 = 40%

Mayweather - 43%
Pacquiao - 40%

Not much between them TBH