War pascal!
Hopkins 1/4 lb(4 oz) over. 2 hours to lose.
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You can see the weigh-in in french here, just click on "Pesee officielle Pascal-Hopkins"
Dawson looks like he's two feet taller than Diaconu. Hopkins looks pissed.
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You can see the weigh-in in french here, just click on "Pesee officielle Pascal-Hopkins"
Dawson looks like he's two feet taller than Diaconu. Hopkins looks pissed.
www.rds.ca
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I recall watching Dirrell get on the windmill to lose what was a little extra weight for the Froch match, I wonder how much it was ?Comment
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Specific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
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Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.Last edited by mathed; 05-20-2011, 03:56 PM.Comment
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Specific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
.................................................. ......................................
Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.
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Specific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
.................................................. ......................................
Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.
as a numbers guy, **** yeah! nice post......... science!Comment
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