War pascal!
Hopkins 1/4 lb(4 oz) over. 2 hours to lose.
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You can see the weigh-in in french here, just click on "Pesee officielle Pascal-Hopkins"
Dawson looks like he's two feet taller than Diaconu. Hopkins looks pissed.
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cong****, I've already posted itYou can see the weigh-in in french here, just click on "Pesee officielle Pascal-Hopkins"
Dawson looks like he's two feet taller than Diaconu. Hopkins looks pissed.
www.rds.ca
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I recall watching Dirrell get on the windmill to lose what was a little extra weight for the Froch match, I wonder how much it was ?Comment
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Specific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
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Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.Last edited by mathed; 05-20-2011, 03:56 PM.Comment
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I do believe this is the most scientific post ever on NSB. You deserve some type of an awardSpecific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
.................................................. ......................................
Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.
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Specific Gravity of H20 (I'm using that instead of the SG of sweat because it's pretty close to the same thing) at 90 degrees = 8.3077 lb/gal. SG of water at 100 F = 8.2877 lb/gal.
Interpolating between the two:
SG @ 98.6 F = 8.3077 lb/gal + [(8.2877-8.3077)/(100-90)lb/gal/F]*(98.6 F - 90.0 F)
= 8.3077 lb/gal - (0.002 lb/gal/F)*(8.6 F)
= 8.3077 lb/gal - 0.0172 lb/gal
SG @ 98.6 F = 8.2905 lb/gal
Next, we use this value and try to relate this to 4 oz and put it in terms of cups of water that he would need to lose.......
Using the fact that 1.0 lb = 16 oz.....[1.0 lb/16 oz], we multiply by the reciprocal of the SG of water or just divide by the SG of H2O @ 98.6 F to yield gal per oz...gal/oz
gal/oz H2O @ 98.6 F = [1.0 lb/16.0 oz]/(8.2905 lb/gal)
gal/oz H2O @ 98.6 F = 0.0075 gal/oz
Since we know that BHOP had to lose a whopping 4.0 oz to make weight, he in turn had to lose a volume of water. This volume of water in terms of gallons is:
Gallons lost to make weight = (0.0075 gal/oz)(4.0 oz)
Gallons lost to make weight = 0.03 gal
We can now equate this amout to cups of water by using the ratio of 16 cups per 1 gal...(16 cups/1 gal)...16 cups/gal by:
Cups of water lost to make weight = (16 cups/gal)*(0.03 gal)
Cups of water lost to make weight = 0.48 cups
We can further equate this to actual oz of water.....
(0.48 cups H2O)*(8.0 fluid oz/cup H2O) = 3.84 oz H2O
.................................................. ......................................
Now how much water volume do or can we release with each piss? I know I can fill a 24.0 Fluid oz bottle to the top pretty easily after a few beverages. I'm certain BHOP only had to venture to the restroom and take a small leak to make weight...there should have been 0 percent effort made on his part and science/mathematics just proved it for you.
as a numbers guy, **** yeah! nice post......... science!Comment

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