Top 3 at 140...Khan, Kotelnik, Maidana

[Steelhammer2011]

Kotelnik's record should be 34-1. He was robbed 3 times. He has wins over Maidana, Alexander, Prime Witter, etc

[RichCCFC]

1. Khan
2. Kotelnik/Maidana
3. Maidana/Kotelnik
4. Bradley
5. Matthyse

[THe TRiNiTY]

Yeah. Bradley has only unified the division with the exception of one tricket and has beaten more top 10 140 pounders than all three of the guys in your top three combined. (Not an over-statement.)

Bradley:
Witter.
Alexander.
Cherry.
Peterson.
Holt.


KHAN/KOTELNIK/MAIDANA:
Malignaggi.
Maidana (twice).
Ortiz.
Kotelnik.

And Ortiz wasn't ranked, but I gave it to you for the **** of it.

Bradley.. then Khan.. then the rest.

[jrosales13]

LOL @ Kotelnik or Maidana being ahead of Bradley.

In rankings Bradley is #1, Khan #2, #3 Kotelnik, #4 you can have either Maidana or Alexander. And, at #5 you can have either Maidana or Alexander.

[jrosales13]

Kotelnik's record should be 34-1. He was robbed 3 times. He has wins over Maidana, Alexander, Prime Witter, etc

Well if Kotelnik was robbed 3 times then you can also say Maidana was robbed against Kotelnik.

[mani1]

LOL @ Kotelnik or Maidana being ahead of Bradley.

In rankings Bradley is #1, Khan #2, #3 Kotelnik, #4 you can have either Maidana or Alexander. And, at #5 you can have either Maidana or Alexander.

Agree with this.

[Phil Ivey]

How is Kotelnik ranked so low, I put him above Ortiz and Judah.

[daggum]

1. gavin rees

[Squizz]

Bradley.. then Khan.. then the rest.

I'd love to see Bradley fight Kahn. Bradley is the best in the division.

[Squizz]

LOL @ Kotelnik or Maidana being ahead of Bradley.

In rankings Bradley is #1, Khan #2, #3 Kotelnik, #4 you can have either Maidana or Alexander. And, at #5 you can have either Maidana or Alexander.

Good post.