Kessler will beat prince arthur

[catalinul]

Nice try backing out of what you said. Undefeated means crap to you though right so your statement about Ottke by your logic means crap right?

Yes undefeated means crap to me.

Translation it means being undefeated doesn't mean much as anyone can pad they're record to 100-0 and not fight anybody.

[lparm]

Yes undefeated means crap to me.

Translation it means being undefeated doesn't mean much as anyone can pad they're record to 100-0 and not fight anybody.

So Calzaghe padded his record? This gets funnier every time you post.

[Tom_Tocca]

Why Tom?

What happened?

I linked one of my vids for BS and the article about Pirog on the European Board and 2 days later I was banned for spamming.

A further 2 days, I couldn't even find my username via my email account...I wrote a mail to the site-admin but never got an answer...

[catalinul]

So Calzaghe padded his record? This gets funnier every time you post.

To a certain degree he did.

Fighting guys like Mario Veit(rematching him after you stopped him altough you didn't wanna rematch Hopkins),Tucker Pudwill,Peter Manfredo,etc is padding the record on a world level.

Basically what I'm saying is that his record is not impressive.Certainly not more impressive than de la Hoya's.

[catalinul]

I linked one of my vids for BS and the article about Pirog on the European Board and 2 days later I was banned for spamming.

A further 2 days, I couldn't even find my username via my email account...I wrote a mail to the site-admin but never got an answer...

Same **** happened to me.

When I wrote him you know what he replied?

''Go join boxingscene,you will fit better there...''

Lol.

[Ryn0]

So Calzaghe padded his record? This gets funnier every time you post.

Man, your ******ed. You obviously don't get what he's saying.

He's saying being undefeated means nothing IF you don't fight anyone, not that Joe didn't fight anyone. He saying Joe may be undefeated but he DIDN'T fight the calibre of fighter De La Hoya did, whether Oscar lost or not.

I'm a big Joe fan, but I'm inclined to agree with this.

[catalinul]

Man, your ******ed. You obviously don't get what he's saying.

He's saying being undefeated means nothing IF you don't fight anyone, not that Joe didn't fight anyone. He saying Joe may be undefeated but he DIDN'T fight the calibre of fighter De La Hoya did, whether Oscar lost or not.

I'm a big Joe fan, but I'm inclined to agree with this.

Yes.That's exactly what I'm saying.

Oh and I'm a Calzaghe fan myself.I always liked his in ring inteligence to find a way always to get out of ****.

[lparm]

To a certain degree he did.

Fighting guys like Mario Veit(rematching him after you stopped him altough you didn't wanna rematch Hopkins),Tucker Pudwill,Peter Manfredo,etc is padding the record on a world level.

Basically what I'm saying is that his record is not impressive.Certainly not more impressive than de la Hoya's.

DLH fought tougher competition but so did SRL and he came away the best of his era. You can't say DLH is awesome without looking at the fact he lost to all the prime ATGs he fought.

[lparm]

Man, your ******ed. You obviously don't get what he's saying.

He's saying being undefeated means nothing IF you don't fight anyone, not that Joe didn't fight anyone. He saying Joe may be undefeated but he DIDN'T fight the calibre of fighter De La Hoya did, whether Oscar lost or not.

I'm a big Joe fan, but I'm inclined to agree with this.

You proved my point when you said "not that Joe didn't fight anyone." He was saying undefeated records means "crap" to him but JC did fight the best so both your points about his record is ******ed dummy. Think about it how can you bash JCs record and then say he fought tough guys doesn't make sense does it.

[catalinul]

DLH fought tougher competition but so did SRL and he came away the best of his era. You can't say DLH is awesome without looking at the fact he lost to all the prime ATGs he fought.

Yeah but DLH always fought the best and that counts a lot.

To me I rank him higher than Calzaghe.