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Testing the BSL Knowledge on binomial coefficients.

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  • #31
    Originally posted by Spartacus Sully View Post
    and?

    and what?

    its not quite 2 but its infinatly close to 2 in such a way that reguardless of how close to 2 a number is that you give me i can use the equation to create a number closer to 2.

    thus in math you can think of it as being 2, but really its just infanity close to 2.

    if you simplify the equation, you will see that it is actually a binomial algebraic expression, thus the answer should be two integer numbers.

    btw infinity is not close to 2.

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    • #32

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      • #33
        Originally posted by crookshanks View Post
        a simple equation. no degree is needed to solve this.

        x=√(2+√(2+√(2+………∞
        Ok.

        Let x = √(2+√(2+√(2+………∞

        Squaring both sides yields

        x^2 = 2 + √(2+√(2+√(2+………∞

        which implies

        x^2 = 2 + x ----> x^2 - x - 2 = 0 -----> (x - 2)(x + 1) = 0

        ----> x = 2 or x = -1

        But the square root of a number can never be negative so, x = 2. QED

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        • #34
          Haha nice math thread.

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          • #35
            Originally posted by Spartacus Sully View Post
            and?

            and what?

            its not quite 2 but its infinatly close to 2 in such a way that reguardless of how close to 2 a number is that you give me i can use the equation to create a number closer to 2.

            thus in math you can think of it as being 2, but really its just infanity close to 2.
            LOL!!!

            Sully is on a roll!!!!

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