Daiki, Tomoki Kameda Land on Koki's Card on 12/4
By Miguel Rivera
For the third time, all three of the fighting Kameda brothers will be on the same card. All three brothers will appear on a card on December 4 in Osaka, Japan. In the main event, the World Boxing Association (WBA) "regular" champion Koki Kameda will face Mexico's Hugo "Cautito" Ruiz.
Daiki Kameda, who has a record of 25 wins, 16 by knockout and only three losses, will face James Mokoginta of Indonesia, who has a record of 24 wins, 12 by knockout, eight losses and a draw. Tomoki, the youngest of the three, will take on Filipino contender Rey Las Piñas.
Japanese fans is really surprised. Because most fans didn't believe it that Koki Kameda fight against Hugo Ruiz. Kameda never does the fight without winning chances. This is a usual way of kameda. Japanese media call kameda "Naniwa-no-Token". "Naniwa-no-Token" denoted…Comment by nycsmooth on 11-20-2012
Tomoki's the 1 I follow but the filipino's no contender @ 17-6...a stay busy bout till he heads bk 2 Mexico...Post a Comment - View More User Comments (2)